JEE Mains · Maths · STD 11 - 9. straight line
Two sides of a parallelogram are along the lines, \(x + y = 3\) and \(x -y + 3 = 0\). If its diagonals intersect at \((2, 4)\), then one of its vertex is
- A \((3, 5)\)
- B \((2, 1)\)
- C \((2, 6)\)
- D \((3, 6)\)
Answer & Solution
Correct Answer
(D) \((3, 6)\)
Step-by-step Solution
Detailed explanation
Intersection point is \(A(0,3)\) \(M=(4,6)\) \(B \Rightarrow \left( {1,2} \right),D \to \left( {3,6} \right)\)
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