JEE Mains · Maths · STD 11 - 14. probability
In a class of \(60\) students, \(40\) opted for \(NCC,\,30\) opted for \(NSS\) and \(20\) opted for both \(NCC\) and \(NSS.\) If one of these students is selected at random, then the probability that the student selected has opted neither for \(NCC\) nor for \(NSS\) is
- A \(\frac {1}{6}\)
- B \(\frac {1}{3}\)
- C \(\frac {2}{3}\)
- D \(\frac {5}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac {1}{6}\)
Step-by-step Solution
Detailed explanation
\(A \rightarrow\) opted \(\mathrm{NCC}\) \(\mathrm{B} \rightarrow\) opted \(\mathrm{NSS}\) \(\therefore \) \(P \text { (neither } A \text { nor } B)=\frac{10}{60}=z \frac{1}{6}\)
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