JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Let \(A =\left(\begin{array}{cc} m & n \\ p & q \end{array}\right), d =| A | \neq 0| A - d (\operatorname{Adj} A )|=0\). Then
- A \((1+ d )^2=( m + q )^2\)
- B \(1+ d ^2=( m + q )^2\)
- C \((1+ d )^2= m ^2+ q ^2\)
- D \(1+ d ^2= m ^2+ q ^2\)
Answer & Solution
Correct Answer
(A) \((1+ d )^2=( m + q )^2\)
Step-by-step Solution
Detailed explanation
\(A =\left[\begin{array}{cc} m & n \\ p & q \end{array}\right], \quad| A - d (\operatorname{adj} A )|=0\)…
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