JEE Mains · Maths · STD 11 - 14. probability
In a box, there are \(20\) cards, out of which \(10\) are lebelled as \(\mathrm{A}\) and the remaining \(10\) are labelled as \(B\). Cards are drawn at random, one after the other and with replacement, till a second \(A-\)card is obtained. The probability that the second \(A-\)card appears before the third \(B-\)card is
- A \(\frac{11}{16}\)
- B \(\frac{13}{16}\)
- C \(\frac{9}{16}\)
- D \(\frac{15}{16}\)
Answer & Solution
Correct Answer
(A) \(\frac{11}{16}\)
Step-by-step Solution
Detailed explanation
\(A:\) Event when card \(A\) is drawn \(\mathrm{B}:\) Event when card \(\mathrm{B}\) is drawn. \(\mathrm{P}(\mathrm{A})=\mathrm{P}(\mathrm{B})=\frac{1}{2}\) Required probability \(=\mathrm{P}(\mathrm{AA} \text { or }(\mathrm{AB}) \mathrm{A}\) or…
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