JEE Mains · Maths · STD 12 - 6. Application of derivatives
Let \(S=(-1, \infty)\) and \(f: S \rightarrow \mathbb{R}\) be defined as \(f(x)=\int_{-1}^x\left(e^1-1\right)^{11}(2 t-1)^5(t-2)^7(t-3)^{12}(2 t-10)^{61} d t\) Let \(p=\) Sum of square of the values of \(x\), where \(\mathrm{f}(\mathrm{x})\) attains local maxima on \(\mathrm{S}\). and \(\mathrm{q}=\) Sum of the values of \(x\), where \(f(x)\) attains local minima on \(S\). Then, the value of \(p^2+2 q\) is
- A \(28\)
- B \(27\)
- C \(25\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(27\)
Step-by-step Solution
Detailed explanation
\(f^{\prime}(x)=\left(e^x-1\right)^{11}(2 x-1)^5(x-2)^7(x-3)^{12}(2 x-10)^{61}\) Local minima at \(\mathrm{x}=\frac{1}{2}, \mathrm{x}=5\) Local maxima at \(\mathrm{x}=0, \mathrm{x}=2\) \(\therefore \mathrm{p}=0+4=4, \mathrm{q}=\frac{1}{2}+5=\frac{11}{2}\) Then…
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