JEE Mains · Maths · STD 12 - 1. relation and function
Let \(A=\{(x, y): 2 x+3 y=23, x, y \in N\}\) and \(B=\{x:(x, y) \in A\}\). Then the number of one-one functions from \(\mathrm{A}\) to \(\mathrm{B}\) is equal to ................
- A \(24\)
- B \(28\)
- C \(42\)
- D \(11\)
Answer & Solution
Correct Answer
(A) \(24\)
Step-by-step Solution
Detailed explanation
\(2 x+3y=23 \) \(x=1 \) \( y=7 \) \(x=4 \) \( y=5 \) \(x=7 \) \( y=3 \) \(x=10 \) \( y=1 \) \(A \) \( B \) \((1,7) \) \( 1 \) \((4,5) \) \( 4 \) \((7,3) \) \( 7 \) \((10,1) \) \( 10\) The number of one-one functions from \(\mathrm{A}\) to \(\mathrm{B}\) is equal to \(4\) !
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