JEE Mains · Maths · STD 11 - 9. straight line
In a \(\triangle A B C\), suppose \(y=x\) is the equation of the bisector of the angle \(B\) and the equation of the side \(A C\) is \(2 x-y=2\). If \(2 A B=B C\) and the point \(A\) and \(B\) are respectively \((4,6)\) and \((\alpha, \beta)\), then \(\alpha+2 \beta\) is equal to
- A \(42\)
- B \(39\)
- C \(48\)
- D \(45\)
Answer & Solution
Correct Answer
(A) \(42\)
Step-by-step Solution
Detailed explanation
\( \mathrm{AD}: \mathrm{DC}=1: 2 \) \( \frac{4-\alpha}{6-\alpha}=\frac{10}{8} \) \( \alpha=\beta \) \( \alpha=14 \text { and } \beta=14\)
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