JEE Mains · Maths · STD 11 - 1. set theory
Two newspaper \(A\) and \(B\) are published in a city. It is known that \(25\%\) of the city populations reads \(A\) and \(20\%\) reads \(B\) while \(8\%\) reads both \(A\) and \(B\). Further, \(30\%\) of those who read \(A\) but not \(B\) look into advertisements and \(40\%\) of those who read \(B\) but not \(A\) also look into advertisements, while \(50\%\) of those who read both \(A\)and \(B\) look into advertisements. Then the percentage of the population who look into advertisement is
- A \(12.8\)
- B \(13.5\)
- C \(13.9\)
- D \(13\)
Answer & Solution
Correct Answer
(C) \(13.9\)
Step-by-step Solution
Detailed explanation
Let population \(=\,100\) \(n(A)\, = \,25\) \(n(B)\, = \,20\) \(n(A \cap B)\, = \,8\) \(n(A \cap \bar B)\, = \,17\) \(n(\bar A \cap B)\, = \,12\) Now \(\%\) of th population who look advertisement \(=\,\frac {30}{100}\times 17\,+\) \(\frac {40}{100}\times 12\,+\)…
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