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JEE Mains · Maths · STD 12 - 9. differential equations

Let \(y = y(x)\) be the solution of the differential equation \(x\sin\left(\dfrac{y}{x}\right)dy = \left(y\sin\left(\dfrac{y}{x}\right) - x\right)dx\), \(y(1) = \dfrac{\pi}{2}\) and let \(\alpha = \cos\left(\dfrac{y(e^{12})}{e^{12}}\right)\). Then the number of integral values of \(p\), for which the equation \(x^2 + y^2 - 2px + 2py + \alpha + 2 = 0\) represents a circle of radius \(r \leq 6\), is __________.

  1. A 6
  2. B 12
  3. C 15
  4. D 18
Verified Solution

Answer & Solution

Correct Answer

(A) 6

Step-by-step Solution

Detailed explanation

Given the differential equation: \(x\sin\left(\dfrac{y}{x}\right)dy = \left(y\sin\left(\dfrac{y}{x}\right) - x\right)dx\) Rearranging the terms, we get: \(x\sin\left(\dfrac{y}{x}\right)dy - y\sin\left(\dfrac{y}{x}\right)dx = -xdx\) Dividing both sides by \(x^2\):…
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