JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
If one of the diameters of the circle \(x^{2}+y^{2}-2 x-6 y+6=0\) is a chord of another circle \('C'\), whose center is at \((2,1),\) then its radius is..........
- A \(2\)
- B \(3\)
- C \(6\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(x^{2}+y^{2}+2 x-6 y+6=0\) center \((1,3)\) radius \(=2\) distance between \((1,3)\) and \((2,1)\) is \(\sqrt{5}\) \(\therefore(\sqrt{5})^{2}+(2)^{2}=r^{2}\) \(\Rightarrow r =3\)
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