JEE Mains · Maths · STD 11 - 12. limits
\(\mathop {\lim }\limits_{x \to 3} \frac{{\sqrt {3x} - 3}}{{\sqrt {2x - 4} - \sqrt 2 }}\) is equal to
- A \(\sqrt 3 \)
- B \(\frac{1}{{\sqrt 2 }}\)
- C \(\frac{{\sqrt 3 }}{2}\)
- D \(\frac{1}{{2\sqrt 2 }}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{{\sqrt 2 }}\)
Step-by-step Solution
Detailed explanation
Let \(A = \,\,\,\mathop {\lim }\limits_{x \to 3} \frac{{\sqrt {3x} - 3}}{{\sqrt {2x - 4} - \sqrt 2 }}\) Rationalise…
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