JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If \(\theta\) denotes the acute angle between the curves, \(y = 10 - x^2\) and \(y = 2 + x^2\) at a point of their intersection, then \(|\tan \,\theta |\) is equal to
- A \(\frac{4}{9}\)
- B \(\frac{8}{15}\)
- C \(\frac{7}{17}\)
- D \(\frac{8}{17}\)
Answer & Solution
Correct Answer
(B) \(\frac{8}{15}\)
Step-by-step Solution
Detailed explanation
\(y = {x^2} + 2\) and \(y = 10 - {x^2}\) Meet at \(\left( { \pm 2,6} \right)\) \( \Rightarrow {m_1} = 4\) and \({m_2} = - 4\) \(\left| {\tan \theta } \right| = \frac{8}{{15}}\)
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