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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

Let the parabola \(y = x^2 + px + q\) passing through the point \((1, -1)\) be such that the distance between its vertex and the \(x\)-axis is minimum. Then the value of \(p^2 + q^2\) is:

  1. A \(2\)
  2. B \(4\)
  3. C \(5\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

Given the equation of the parabola \(y = x^2 + px + q\). Since it passes through \((1, -1)\), we have: \(-1 = 1 + p + q \Rightarrow q = -p - 2\) The vertex of the parabola \(y = x^2 + px + q\) occurs at \(x = -\dfrac{p}{2}\). The \(y\)-coordinate of the vertex is:…
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