JEE Mains · Maths · STD 11 - 9. straight line
Let \(A B C\) be a triangle formed by the lines \(7 x-6 y+3=0, x+2 y-31=0\) and \(9 x-2 y-19=0\). Let the point \((h, k)\) be the image of the centroid of \(\Delta A B C\) in the line \(3 x+6 y-53=0\). Then \(h^2+k^2+h k\) is equal to:
- A 47
- B 37
- C 36
- D 40
Answer & Solution
Correct Answer
(B) 37
Step-by-step Solution
Detailed explanation
\(\therefore \text { centroid of } \triangle \mathrm{ABC}\) \(=\left(\frac{9+3+5}{3}, \frac{11+4+13}{3}\right)\) \(=\left(\frac{17}{3}, \frac{28}{3}\right)\) Let image of centroid with respect to line mirror is \((\mathrm{h}, \mathrm{k})\)…
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