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JEE Mains · Maths · STD 12 - 10. vector algebra

Consider a \(\Delta A B C\) where \(A(1,3,2), B(-2,8,0)\) and \(C(3,6,7)\). If the angle bisector of \(\angle B A C\) meets the line \(B C\) at \(D\), then the length of the projection of the vector \(\overrightarrow{A D}\) on the vector \(\overrightarrow{A C}\) is :

  1. A \(\frac{37}{2 \sqrt{38}}\)
  2. B \(\frac{\sqrt{38}}{2}\)
  3. C \(\frac{39}{2 \sqrt{38}}\)
  4. D \(\sqrt{19}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{37}{2 \sqrt{38}}\)

Step-by-step Solution

Detailed explanation

Given, \(A(1,3,2), B(-2,8,0) \& C(3,6,7)\) And angle bisector of \(\angle B A C\) meets the line \(B C\) at \(D\), Now, plotting the diagram we get, Now, finding \(\overrightarrow{A C}=2 \hat{i}+3 \hat{j}+5 \hat{k}\) \(\Rightarrow|\overrightarrow{A C}|=\sqrt{4+9+25}=\sqrt{38}\)…