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JEE Mains · Maths · STD 11 - 6. permutation and combination

The number of numbers greater than 5000, less than 9000 and divisible by 3, that can be formed using the digits 0, 1, 2, 5, 9, if the repetition of the digits is allowed, is ___ .

  1. A 40
  2. B 42
  3. C 44
  4. D 46
Verified Solution

Answer & Solution

Correct Answer

(B) 42

Step-by-step Solution

Detailed explanation

(1) all different 5, 0, 1, 9 \(\Rightarrow\lfloor 3=6\) ways (2) 2 alike, 2 different \(5,0,0,1 \Rightarrow 3\) ways \(5,1,1,2 \Rightarrow 3\) ways \(5,2,2,0 \Rightarrow 3\) ways \(5,2,2,9 \Rightarrow 3\) ways \(5,5,0,2 \Rightarrow 6\) ways \(5,5,2,9 \Rightarrow 6\) ways…