JEE Mains · Maths · STD 11 - Trigonometrical equations
From the base of a pole of height \(20\) meter, the angle of elevation of the top of a tower is \(60^{\circ}\). The pole subtends an angle \(30^{\circ}\) at the top of the tower. Then the height of the tower is
- A \(15 \sqrt{3}\)
- B \(20 \sqrt{3}\)
- C \(20+10 \sqrt{3}\)
- D \(30\)
Answer & Solution
Correct Answer
(D) \(30\)
Step-by-step Solution
Detailed explanation
\(PT =\frac{ h }{\sqrt{3}}= AB\) \(\frac{A B}{h-20}=\sqrt{3}\) \(h=3(h-20)\) \(h=30\)
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