JEE Mains · Maths · STD 12 - 11. three dimension geometry
A plane passing through the point \((3,1,1)\) contains two lines whose direction ratios are \(1 ,-2,2\) and \(2,3,-1\) respectively. If this plane also passes through the point \((\alpha,-3,5),\) then \(\alpha\) is equal to
- A \(-10\)
- B \(5\)
- C \(10\)
- D \(-5\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
Hence normal is \(\perp\) " to both the lines so normal vector to the plane is \(\overrightarrow{\mathrm{n}}=(\hat{\mathrm{i}}-2 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}) \times(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-\hat{\mathrm{k}})\)…
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