ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

Let \(r_{1}\) and \(r_{2}\) be the radii of the largest and smallest circles, respectively, which pass through the point \((-4,1)\) and having their centres on the circumference of the circle \(x^{2}+y^{2}+2 x+4 y-4= 0.\) If \(\frac{r_{1}}{r_{2}}=a+b \sqrt{2}\), then \(a+b\) is equal to:

  1. A \(3\)
  2. B \(11\)
  3. C \(5\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

Centre of smallest circle is \(\mathrm{A}\) Centre of largest circle is \(\mathrm{B}\) \(r_{2}=|C P-C A|=3 \sqrt{2}-3\) \(r_{1}=C P+C B=3 \sqrt{2}+3\) \(\frac{r_{1}}{r_{2}}=\frac{(3 \sqrt{2}+3)^{2}}{9}=(\sqrt{2}+1)^{2}=3+2 \sqrt{2}\) \(a=3, b=2\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app