JEE Mains · Maths · STD 11 - 13. statistics
Let \(\mathrm{M}\) denote the median of the following frequency distribution then \(20\) \(M\) is equal to :
| Class | \(0-4\) | \(4-8\) | \(8-12\) | \(12-16\) | \(16-20\) |
| Freq | \(3\) | \(9\) | \(10\) | \(8\) | \(6\) |
- A \(416\)
- B \(104\)
- C \(52\)
- D \(208\)
Answer & Solution
Correct Answer
(D) \(208\)
Step-by-step Solution
Detailed explanation
Class Frequency Cumulative frequency \(0-4\) \(3\) \(3\) \(4-8\) \(9\) \(12\) \(8-12\) \(10\) \(22\) \(12-16\) \(8\) \(30\) \(16-20\) \(6\) \(36\) \( \mathrm{M}=1+\left(\frac{\frac{\mathrm{N}}{2}-\mathrm{C}}{\mathrm{f}}\right) \mathrm{h} \)…
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