JEE Mains · Maths · STD 12 - 10. vector algebra
Let \( \vec{a}=2\hat{i}-5\hat{j}+5\hat{k} \) and \( \vec{b}=\hat{i}-\hat{j}+3\hat{k}. \) If \( \vec{c} \) is a vector such that
\( 2(\vec{a}\times\vec{c})+3(\vec{b}\times\vec{c})=\vec{0} \) and \( (\vec{a}-\vec{b})\cdot\vec{c}=-97, \) then \( |\vec{c}\times \hat{k}|^{2} \) is equal to
- A 193
- B 233
- C 218
- D 205
Answer & Solution
Correct Answer
(C) 218
Step-by-step Solution
Detailed explanation
\(2(\vec{a} \times \vec{c})+3(\vec{b} \times \vec{c})=0 \) \(\Rightarrow(2 \vec{a}+3 \vec{d}) \times \vec{c}=0 \Rightarrow \vec{c}=\lambda(2 \vec{a}+3 \vec{d})\) \(\Rightarrow \vec{c}=\lambda(7 i-13 j+19 k)\) Now…
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