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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

A hyperbola passes through the foci of the ellipse \(\frac{ x ^{2}}{25}+\frac{ y ^{2}}{16}=1\) and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities in one, then the equation of the hyperbola is ...... .

  1. A \(\frac{x^{2}}{9}-\frac{y^{2}}{25}=1\)
  2. B \(\frac{x^{2}}{9}-\frac{y^{2}}{16}=1\)
  3. C \(x^{2}-y^{2}=9\)
  4. D \(\frac{x^{2}}{9}-\frac{y^{2}}{4}=1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{x^{2}}{9}-\frac{y^{2}}{16}=1\)

Step-by-step Solution

Detailed explanation

For ellipse \(e_{1}=\sqrt{1-\frac{b^{2}}{a^{2}}}=\frac{3}{5}\) for hyperbola \(e _{2}=\frac{5}{3}\) Let hyperbola be \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) \(\because\) it passes through \((3,0) \Rightarrow \frac{9}{a_{2}}=1\) \(\Rightarrow a ^{2}=9\)…
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