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JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
Which of the following would not give \(2-\) phenylbutane as the major product in a Friedel-Crafts alkylation reaction ?
- A \(1-\) butene \(+ HF\)
- B \(2-\) butanol \(+ H_2SO_4\)
- C Butanoyl chloride \(+ AlCl_3\) then \(Zn, HCl\)
- D Butyl choloride \(+ AlCl_3\)
Answer & Solution
Correct Answer
(C) Butanoyl chloride \(+ AlCl_3\) then \(Zn, HCl\)
Step-by-step Solution
Detailed explanation
The fridal - crafts alkylation reaction will give propyl phenyl ketone which further on clemmenson's reduction will give butyl benzene \({C_6}{H_6}\, + \,C{H_3}C{H_2}C{H_2}COCl\,\xrightarrow{{AlC{l_3}}}\) \({C_6}{H_5}COC{H_2}C{H_2}C{H_3}\,\xrightarrow{{Zn - Hg\,/\,HCl}}\)…
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