JEE Mains · Chemistry · STD 11 - 2. structure of atom
The wavelength of spectral line obtained in the spectrum of \(LI^{2+}\) ion, when the transition takes place between two levels whose sum is 4 and difference is 2, is
- A \(2.28 \times 10^{-7} cm\)
- B \(2.28 \times 10^{-6} cm\)
- C \(1.14 \times 10^{-7} cm\)
- D \(1.14 \times 10^{-6} cm\)
Answer & Solution
Correct Answer
(D) \(1.14 \times 10^{-6} cm\)
Step-by-step Solution
Detailed explanation
\(n _1 \rightarrow\) lower energy level \(n _2 \rightarrow\) higher energy level \(n _1+ n _2=4, \quad n _2=3\) \(n _2- n _1=2, n _1=1\) Rydberg's formula : \(\frac{1}{\lambda}= R _{ H } Z ^2\left[\frac{1}{ n _1^2}-\frac{1}{ n _2^2}\right]\)…
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