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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

The number of atoms in \(8\, \mathrm{~g}\) of sodium is \(\mathrm{x} \times 10^{23}.\) The value of \(\mathrm{x}\) is ...... .(Nearest integer) \(\left[\right.\) Given \(: \mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23}\, \mathrm{~mol}^{-1}\), Atomic mass of \(\mathrm{Na}=23.0\, \mathrm{u}]\)

  1. A \(6\)
  2. B \(8\)
  3. C \(2\)
  4. D \(34\)
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Answer & Solution

Correct Answer

(C) \(2\)

Step-by-step Solution

Detailed explanation

\(\text { No. of atoms }=\frac{8}{23} \times 6.02 \times 10^{23}= 2.09 \times 10^{23}\) \(\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\simeq 2 \times 10^{23}\)…
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