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JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

The geometry of \(XeOF_4\) by \(VSEPR\) theory is

  1. A pentagonal planar
  2. B octahedral
  3. C square pyramidal
  4. D trigonal bipyramidal
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Answer & Solution

Correct Answer

(C) square pyramidal

Step-by-step Solution

Detailed explanation

In \(XeOF_4\), \(Xe\) is \(sp^3d^2\), hybridised having \(6\) bond pairs and \(1\) lone pair
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