JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Molecular \(AB\) has a bond length of \(1.61\,\mathop A\limits^o \) and a dipole moment of \(0.38\, D\). The fractional charge on each atom (absolute magnitude) is \((e_0\, = 4.802\times10^{-10}\, esu)\)
- A \(0.5\)
- B \(0.05\)
- C \(0\)
- D \(1.0\)
Answer & Solution
Correct Answer
(B) \(0.05\)
Step-by-step Solution
Detailed explanation
\(1\,e = 1.602 \times {10^{ - 19}}\,C\) \(1\,esu = 3.33 \times {10^{ - 10}}\,C\) \(\frac{{1\,e}}{{1\,esu}} = \frac{{1.602 \times {{10}^{ - 19}}\,C}}{{3.33 \times {{10}^{ - 10}}\,C}}\) \(1\,e = 4.802 \times {10^{ - 10}}\,esu\,\) Dipole moment \(= q \times \) distance…
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