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JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
The addition of \(HI\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because
- A \(HI\) is a strong reducing agent
- B \(H-I\) bond is too strong to be broken homolytically
- C \(I\) atom combines with \(H\) atom to give back \(HI\)
- D Iodine atom is not reactive enough to add across a double bond
Answer & Solution
Correct Answer
(D) Iodine atom is not reactive enough to add across a double bond
Step-by-step Solution
Detailed explanation
\(HI\) does not exhibit peroxide effect. \(HI\) bond although dissociates easily into iodine radicals, they being bigger in size are not much reactive but recombine together to form iodine molecule
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