JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The process with negative entropy change is
- A Dissociation of \(CaSO_4(s)\) to \(CaO(s)\) and \(SO_3(g)\)
- B Sublimation of dry ice
- C Dissolution of iodine in water
- D Synthesis of ammonia from \(N_2\) and \(H_2\)
Answer & Solution
Correct Answer
(D) Synthesis of ammonia from \(N_2\) and \(H_2\)
Step-by-step Solution
Detailed explanation
\(CaS{O_4}(s) \to CaO(s) + S{O_3}(g)\) \(C{O_2}(s) \to C{O_2}(g)\) \({I_2} \to {I_2}(aq)\) \({N_2}(g) + 3{H_2}(g) \to 2N{H_3}(g)\) \({N_2}(g) + 3{H_2} \leftrightarrow 2N{H_3}(g)\) \(\Delta S = 2\Delta {S_{N{H_3}}} - [\Delta {S_{{N_2}}} + 3\Delta {S_{{H_2}}}]\) There is decrease…
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