JEE Mains · Chemistry · STD 12 - 7. Alcohol, phenol and ethers
One mole of phenol is treated with dilute HNO\(_3\) at \(298\) K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is _____ \(\times 10^{-1}\) %
(Given molar mass in g mol\(^{-1}\) H:\(1\), C:\(12\), N:\(14\), O:\(16\))
- A 165
- B 170
- C 175
- D 180
Answer & Solution
Correct Answer
(C) 175
Step-by-step Solution
Detailed explanation
When phenol is treated with dilute \(\text{HNO}_3\) at \(298\text{ K}\), it undergoes electrophilic aromatic substitution to give a mixture of ortho-nitrophenol and para-nitrophenol. The mixture is separated by steam distillation. Ortho-nitrophenol is steam volatile due to…
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