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JEE Mains · Chemistry · STD 12 - 7. Alcohol, phenol and ethers

One mole of phenol is treated with dilute HNO\(_3\) at \(298\) K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is _____ \(\times 10^{-1}\) %
(Given molar mass in g mol\(^{-1}\) H:\(1\), C:\(12\), N:\(14\), O:\(16\))

  1. A 165
  2. B 170
  3. C 175
  4. D 180
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Answer & Solution

Correct Answer

(C) 175

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Detailed explanation

When phenol is treated with dilute \(\text{HNO}_3\) at \(298\text{ K}\), it undergoes electrophilic aromatic substitution to give a mixture of ortho-nitrophenol and para-nitrophenol. The mixture is separated by steam distillation. Ortho-nitrophenol is steam volatile due to…
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