JEE Mains · Chemistry · STD 11 - 7. Redox reactions
On charging the lead storage battery, the oxidation state of lead changes from \(x_1\) to \(y_1\) at the anode and from \(x_2\) to \(y_2\) at the cathode. The values of \(x_1, y_1, x_2, y_2\) are respectively :
- A \(+4,+2,0,+2\)
- B \(+2,0,+2,+4\)
- C \(0,+2,+4,+2\)
- D \(+2,0,0,+4\)
Answer & Solution
Correct Answer
(B) \(+2,0,+2,+4\)
Step-by-step Solution
Detailed explanation
For charging of lead storage battery cell reaction is \(2 \mathrm{PbSO}_4(\mathrm{~s})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{Pb}(\mathrm{s})+\mathrm{PbO}_2(\mathrm{~s})+2 \mathrm{H}_2 \mathrm{SO}_4(\mathrm{aq})\) At anode \(\mathrm{PbSO}_4\) reduced back to…
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