JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Hemoglobin contains \(0.34 \%\) of iron by mass. The number of \(Fe\) atoms in \(3.3 g\) of hemoglobin is.(Given : Atomic mass of \(Fe\) is \(56\,u , N _{ A }\) in \(6.022\) \(\left.\times 10^{23} mol ^{-1}\right)\)
- A \(1.21 \times 10^{5}\)
- B \(12.0 \times 10^{16}\)
- C \(1.21 \times 10^{20}\)
- D \(3.4 \times 10^{22}\)
Answer & Solution
Correct Answer
(C) \(1.21 \times 10^{20}\)
Step-by-step Solution
Detailed explanation
No. of Fe atoms \(=\frac{0.34}{100} \times \frac{3.3}{56} \times 6.022 \times 10^{23}\) \(=1.206 \times 10^{20}\)
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