JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
For the electro chemical cell \(\mathrm{M}\left|\mathrm{M}^{2+}\right||\mathrm{X}| \mathrm{X}^{2-}\) If \(\mathrm{E}_{\left(\mathrm{M}^{2+} / \mathrm{M}\right)}^0=0.46 \mathrm{~V}\) and \(\mathrm{E}_{\left(\mathrm{x} / \mathrm{X}^{2-}\right)}^0=0.34 \mathrm{~V}\). Which of the following is correct?
- A \(\mathrm{E}_{\text {cell }}=-0.80 \mathrm{~V}\)
- B \(\mathrm{M}+\mathrm{X} \rightarrow \mathrm{M}^2+\mathrm{X}^2\) is a spontaneous reaction
- C \(\mathrm{M}^{2+}+\mathrm{X}^{2-} \rightarrow \mathrm{M}+\mathrm{X}\) is a spontaneous reaction
- D \(\mathrm{E}_{\text {eell }}=0.80 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{M}^{2+}+\mathrm{X}^{2-} \rightarrow \mathrm{M}+\mathrm{X}\) is a spontaneous reaction
Step-by-step Solution
Detailed explanation
\(\mathrm{M} \mid \mathrm{M}^{+2} \| \mathrm{X} / \mathrm{X}^{2-}\) \(\mathrm{E}_{\text {cell }}^{\circ}=\mathrm{E}_{\mathrm{M} / \mathrm{M}^{+2}}^{\circ}+\mathrm{E}_{\mathrm{X} / \mathrm{X}^{-2}}^{\circ}\) \(=-0.46+0.34=-0.12 \mathrm{~V}\) As…
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