JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Density of 3 M NaCl solution is \(1.25 \mathrm{~g} / \mathrm{mL}\). The molality of the solution is _______.
- A 1.79 m
- B 2.79 m
- C 2 m
- D 3 m
Answer & Solution
Correct Answer
(B) 2.79 m
Step-by-step Solution
Detailed explanation
\begin{aligned} & 3 \mathrm{M} \mathrm{NaCl}, \mathrm{d}_{\text {sol }}=1.25 \mathrm{gm} / \mathrm{mol} \\ & \begin{aligned} \text { Molality } & =\frac{\mathrm{M} \times 1000}{1000 \mathrm{~d}-\mathrm{M} \times \mathrm{M}_{\mathrm{W}}} \\ &…
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