JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Fortification of food with iron is done using \(\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}\). The mass in grams of the \(\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}\) required to achieve 12 ppm of iron in 150 kg of wheat is _______. (Nearest integer)
[Given : Molar mass of \(\mathrm{Fe}, \mathrm{S}\) and O respectively are 56,32 and \(16 \mathrm{~g} \mathrm{~mol}^{-1}\) ]
- A 9
- B 10
- C 11
- D 12
Answer & Solution
Correct Answer
(A) 9
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Let mass of iron }=\mathrm{wg} \\ & \Rightarrow \frac{\mathrm{w}}{150 \times 10^3} \times 10^6=12 \\ & \Rightarrow \mathrm{w}=150 \times 12 \times 10^{-3}=1.8 \mathrm{gm} \end{aligned}\) Let mass of…
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