Cannizaro' s reaction is not given by

C \(CH_3CHO\)
D \(HCHO\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(CH_3CHO\)

Step-by-step Solution

Detailed explanation

Only those aldehydes which do not have \(\alpha - H\) atom undergo Cannizaro's reaction. Hence \(CH_3CHO\) will not undergo Cannizaro's reaction as it has \(3\,\alpha \) \(H\) atoms.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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From JEE Mains

Match List - I with List - II.

List - I	List - II
(A) Electric field inside (distance \(r>0\) from center) of a uniformly charged spherical shell with surface charge density \(\sigma\), and radius R.	(I) \(\sigma / \epsilon_0\)
(B) Electric field at distance \(r >0\) from a uniformly charged infinite plane sheet with surface charge density \(\sigma\).	(II) \(\sigma / 2 \epsilon_0\)
(C) Electric field outside (distance \(r>0\) from center) of a uniformly charged spherical shell with surface charge density \(\sigma\), and radius R.	(III) \(0\)
(D) Electric field between 2 oppositely charged infinite plane parallel sheets with uniform surface charge density \(\sigma\).	(IV) \(\frac{\sigma R^2}{\epsilon_0 r^2}\)

Choose the correct answer from the options given\(\text{ }\)below\(\text{ }\):

JEE Mains 2025 Medium

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\(x_i\)	\(2\)	\(4\)	\(6\)	\(8\)	\(10\)	\(12\)	\(14\)	\(16\)
\(f_i\)	\(4\)	\(4\)	\(\alpha\)	\(15\)	\(8\)	\(\beta\)	\(4\)	\(5\)