JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(\mathrm{CaCO}_3(\mathrm{~s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{CaCl}_2(\mathrm{aq})+\mathrm{CO}_2(\mathrm{~g}) \mathrm{H}_2 \mathrm{O}(\mathrm{l})\)
Consider the above reaction, what mass of \(\mathrm{CaCl}_2\) will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of \(\mathrm{CaCO}_3\) ?
(Given : Molar mass of \(\mathrm{Ca}, \mathrm{C}, \mathrm{O}, \mathrm{H}\) and Cl are 40, \(12,16,1\) and \(35.5 \mathrm{~g} \mathrm{~mol}^{-1}\), respectively)
- A 3.908 g
- B 2.636 g
- C 10.545 g
- D 5.272 g
Answer & Solution
Correct Answer
(C) 10.545 g
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{CaCO}_3+2 \mathrm{HCl} \rightarrow \mathrm{CaCl}_2+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O} \\ & \text { Moles of } \mathrm{CaCO}_3=\frac{1000}{100}=10 \end{aligned}\) Moles of \(\mathrm{HCl}=0.76 \times \frac{250}{1000}=0.19\) (L.R.) Moles of…
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