JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Consider the following species:
BrF\(_5\), XeF\(_5^-\), BF\(_4^-\), ICl\(_4^-\), XeF\(_4\), SF\(_4\), NH\(_4^+\), ClF\(_3\), XeF\(_2\), ICl\(_2^-\)
Number of species having sp\(^3\)d hybridized central atom is __________.
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(D) 4
Step-by-step Solution
Detailed explanation
The steric number \(H\) is calculated as \(H = \dfrac{1}{2}(V + M - C + A)\), where \(V\) is the number of valence electrons on the central atom, \(M\) is the number of monovalent atoms, \(C\) is the cationic charge, and \(A\) is the anionic charge. For \(sp^3d\) hybridization,…
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