JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
An oxide of iron contains \(69.9\%\) iron, its empirical formula, is: (Given: Molar mass of Fe and O are \(56\) and \(16\) g mol\(^{-1}\) respectively.)
- A \(\text{FeO}\)
- B \(\text{Fe}_2\text{O}_3\)
- C \(\text{Fe}_3\text{O}_4\)
- D \(\text{FeO}_3\)
Answer & Solution
Correct Answer
(B) \(\text{Fe}_2\text{O}_3\)
Step-by-step Solution
Detailed explanation
Mass percentage of \(\text{Fe} = 69.9\%\) Mass percentage of \(\text{O} = 100\% - 69.9\% = 30.1\%\) Number of moles of \(\text{Fe} = \dfrac{69.9}{56} = 1.248\) Number of moles of \(\text{O} = \dfrac{30.1}{16} = 1.881\) Molar ratio of \(\text{Fe} : \text{O} = 1.248 : 1.881\)…
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