JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
An artificial cell is made by encapsulating \(0.2 \mathrm{M}\) glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a \(0.05 \mathrm{M}\) solution of \(\mathrm{NaCl}\) at \(300 \mathrm{~K}\) is _______\(\times 10^{-1}\) bar. (Nearest Integer) [Given : \(\mathrm{R}=0.083 \mathrm{~L} \mathrm{bar} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\) ] Assume complete dissociation of \(\mathrm{NaCl}\)
- A \(10\)
- B \(20\)
- C \(25\)
- D \(30\)
Answer & Solution
Correct Answer
(C) \(25\)
Step-by-step Solution
Detailed explanation
\(\mathrm{NaCl} \longrightarrow \mathrm{Na}^{+}+\mathrm{Cl}^{-}\) \(0.05 \mathrm{M} \quad 0.05 \mathrm{M} \quad 0.05 \mathrm{M}\) \(\text { Total } \mathrm{C}_1=0.05+0.05=0.1 \mathrm{M}(\mathrm{NaCl})\) \(\mathrm{C}_2=0.2 \mathrm{M}(\text { glucose })\)…
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