JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
A solution of \(Ni(NO_3)_2\) is electrolysed between platinum electrodes using \(0.1\) Faraday electricity. How many mole of \(Ni\) will be deposited at the cathode?
- A \(0.20\)
- B \(0.05\)
- C \(0.10\)
- D \(0.15\)
Answer & Solution
Correct Answer
(B) \(0.05\)
Step-by-step Solution
Detailed explanation
\(1\,F\) deposits \(1\,g\) equivalent of \(Ni\) or \(1/2\,mole\) of \(Ni\) \(\therefore \,F\) will deposit \(\frac {1}{20}\,=\,0.05\,moles\) of \(Ni\)
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