JEE Mains · Chemistry · STD 11 - 7. Redox reactions

\((A)\) \(HOCl + H _{2} O _{2} \rightarrow H _{3} O ^{+}+ Cl ^{-}+ O _{2}\) \((B)\) \(I _{2}+ H _{2} O _{2}+2 OH ^{-} \rightarrow 2 I ^{-}+2 H _{2} O + O _{2}\) Choose the correct option.

A \(H _{2} O _{2}\) acts as reducing and oxidising agent respectively in equation \((A)\) and \((B)\)
B \(H _{2} O _{2}\) acts as oxidising agent in equation \((A)\) and \((B)\)
C \(H _{2} O _{2}\) acts as reducing agent in equation \((A)\) and \(( B )\)
D \(H _{2} O _{2}\) act as oxidizing and reducing agent respectively in equation \((A)\) and \((B)\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(H _{2} O _{2}\) acts as reducing agent in equation \((A)\) and \(( B )\)

Step-by-step Solution

Detailed explanation

\((A)\) \(HOCl + H _{2} O _{2} \rightarrow H _{3} O ^{+}+ Cl ^{-}+ O _{2}\) In this equation, \(H _{2} O _{2}\) is reducing chlorine from \(+1\) to \(-1\) \((B)\) \(I _{2}+ H _{2} O _{2}+2 OH^- \rightarrow 2 I ^{-}+2 H _{2} O + O _{2}\) In this equation, \(H _{2} O _{2}\) is…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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