ExamBro
ExamBro
JEE Mains · Chemistry · STD 11 - 7. Redox reactions

\(500\) mL of \(0.2\) M MnO\(_4^-\) solution in basic medium when mixed with \(500\) mL of \(1.5\) M KI solution, oxidises iodide ions to liberate molecular iodine. This liberated iodine is then titrated with a standard \(x\) M thiosulphate solution in presence of starch till the end point. If \(300\) mL of thiosulphate was consumed, then the value of \(x\) is __________.

  1. A 1
  2. B 2
  3. C 3
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(A) 1

Step-by-step Solution

Detailed explanation

First, we calculate the millimoles of the reactants: Millimoles of \(\text{MnO}_4^-\) = \(500 \text{ mL} \times 0.2 \text{ M} = 100 \text{ mmol}\) Millimoles of \(\text{I}^-\) = \(500 \text{ mL} \times 1.5 \text{ M} = 750 \text{ mmol}\) In a basic medium, \(\text{MnO}_4^-\) is…