JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is _______.
(Given : Ebullioscopic constant of water \(\left.=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)\)
- A 379.2 K
- B 377.3 K
- C 375.3 K
- D 277.3 K
Answer & Solution
Correct Answer
(B) 377.3 K
Step-by-step Solution
Detailed explanation
\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{i}_1 \mathrm{~m}_1 \mathrm{k}_{\mathrm{b}}+\mathrm{i}_2 \mathrm{~m}_2 \mathrm{k}_{\mathrm{b}} \\ & =1 \times \frac{2}{0.5} \times 0.52+\frac{1 \times 2}{0.5} \times 0.52=4.16 \\ &…
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