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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is _______.
(Given : Ebullioscopic constant of water \(\left.=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)\)

  1. A 379.2 K
  2. B 377.3 K
  3. C 375.3 K
  4. D 277.3 K
Verified Solution

Answer & Solution

Correct Answer

(B) 377.3 K

Step-by-step Solution

Detailed explanation

\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{i}_1 \mathrm{~m}_1 \mathrm{k}_{\mathrm{b}}+\mathrm{i}_2 \mathrm{~m}_2 \mathrm{k}_{\mathrm{b}} \\ & =1 \times \frac{2}{0.5} \times 0.52+\frac{1 \times 2}{0.5} \times 0.52=4.16 \\ &…

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