JEE Advanced · Physics · 25. Wave Optics
Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are \(\beta_{G}, \beta_{R}\) and \(\beta_{B}\), respectively. Then,
- A \(\beta_{G}>\beta_{B}>\beta_{R}\)
- B \(\beta_{B}>\beta_{G}>\beta_{R}\)
- C \(\beta_{R}>\beta_{B}>\beta_{G}\)
- D \(\beta_{R}>\beta_{G}>\beta_{B}\)
Answer & Solution
Correct Answer
(D) \(\beta_{R}>\beta_{G}>\beta_{B}\)
Step-by-step Solution
Detailed explanation
We know that fringe width, \(\beta=\frac{\lambda D}{d}\) \(\because \quad \lambda_{R}>\lambda_{\mathrm{G}}>\lambda_{B} \quad \therefore \beta_{R}>\beta_{G}>\beta_{B}\)
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