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JEE Advanced · Physics · 11. Properties of Fluids

Paragraph:
A small spherical monoatomic ideal gas bubble \(\left(\gamma=\frac{5}{3}\right)\) is trapped inside a liquid of density \(\rho_1\) (see figure). Assume that the bubble does not exchange any heat with the liquid. The bubble contains \(n\) moles of gas. The temperature of the gas when the bubble is at the bottom is \(T_0\), the height of the liquid is \(H\) and the atmospheric pressure is \(p_0\) (Neglect surface tension).

Question:
The buoyancy force acting on the gas bubble is (Assume \(R\) is the universal gas constant)

  1. A \(\rho_l n R g T_0 \frac{\left(\rho_0+\rho_l g H\right)^{\frac{2}{5}}}{\left(\rho_0+\rho_l g y\right)^{\frac{7}{5}}}\)
  2. B \(\frac{\rho_l n R g T_0}{\left(\rho_0+\rho_l g H\right)^{\frac{2}{5}}\left[\rho_0+\rho_l g(H-y)\right]^{\frac{3}{5}}}\)
  3. C \(\rho n R g T_0 \frac{\left(\rho_0+\rho_l g H\right)^{\frac{3}{5}}}{\left(\rho_0+\rho_l g y\right)^{\frac{8}{5}}}\)
  4. D \(\frac{\rho_l n R g T_0}{\left(\rho_0+\rho_l g H\right)^{\frac{3}{5}}\left[\rho_0+\rho_l g(H-y)\right]^{\frac{2}{5}}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\rho_l n R g T_0}{\left(\rho_0+\rho_l g H\right)^{\frac{2}{5}}\left[\rho_0+\rho_l g(H-y)\right]^{\frac{3}{5}}}\)

Step-by-step Solution

Detailed explanation

Buoyancy force
Here, and
\(
\begin{aligned}
F & =(\text { volume of bubble })\left(\rho_l\right) g \\
& =\left(\frac{n R T_2}{p_2}\right) p_l g \\
T_2 & =T_0\left[\frac{p_0+p_l g(H-y)}{p_0+\rho_l g H}\right] \\
p_2 & =p_0+p_l(H-y)
\end{aligned}
\)
Substituting the values we get,
\(F=\frac{\rho_n n g T_0}{\left(p_0+\rho_l g H\right)^{2 / 5}\left[p_0+\rho_l g(H-y)\right]^{3 / 5}}\)
\(\therefore\) correct option is (b).
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