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JEE Advanced · Physics · 24. Ray Optics

The focal length of a thin biconvex lens is \(20 \mathrm{~cm}\). When an object is moved from a distance of \(25 \mathrm{~cm}\) in front of it to \(50 \mathrm{~cm}\), the magnification of its image changes from \(m_{25}\) to \(m_{50}\). The ratio \(\frac{m_{25}}{m_{50}}\) is

  1. A 2
  2. B 4
  3. C 6
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(C) 6

Step-by-step Solution

Detailed explanation

\(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\) or
\(
\frac{u}{v}-1=\frac{u}{f}
\)
\(\text { or } \frac{u}{v} =\left(\frac{u+f}{f}\right) \)
\( \therefore m=\frac{v}{u} =\left(\frac{f}{u+f}\right) \)
\( \frac{m_{25}}{m_{50}} =\frac{\left(\frac{20}{-25+20}\right)}{\left(\frac{20}{-50+20}\right)}=6\)
\(\therefore\) answer is 6 .
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