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JEE Advanced · Physics · 27. Atomic Physics

The radius of the orbit of an electron in a Hydrogen-like atom is \(4.5 a _0\), where \(a _0\) is the Bohr radius. Its orbital angular momentum is \(\frac{3 h}{2 \pi}\). It is given that \(h\) is Planck's constant and R is Rydberg constant. the possible wavelength \((s)\), when the atom de-excites, is (are)

  1. A 9 3 2 R
  2. B 9 1 6 R
  3. C 9 5 R
  4. D 4 3 R
Verified Solution

Answer & Solution

Correct Answer

(C) 9 5 R

Step-by-step Solution

Detailed explanation

R n = 4.5 a 0   ⇒   a 0 n 2 / z = 4.5  a 0
∴    n = 3 z = 2
L = mvr = 3 h 2 π as n = 3 , z = 2

1 λ = Rz 2 1 n f 2 - 1 n 1 2
1 λ 3 1 = R 4 1 1 - 1 9 = 4 R 8 9 λ 3 1 = 9 3 2 R
1 λ 2 1 = R 4 1 1 - 1 4 = 3 4 4 R λ 2 1 = 1 3 R
1 λ 3 2 = R 4 1 4 - 1 9 = 5 3 6 4 R λ 3 2 = 9 5 R
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