JEE Advanced · Physics · 9. Gravitation
The distance between two stars of masses and is . Here is the mean distance between the centres of the Earth and the Sun, and is the mass of the Sun. Two stars orbit around their common centre of mass in circular orbits with period , where is the period of Earth's revolution around the Sun. The value of is _____.
- A 3
- B 6
- C 9
- D 12
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
\(T=\frac{2 \pi R^{3 / 2}}{\sqrt{G M_S}}\)
For binary stars,
\(T^{\prime}=\frac{2 \pi r^{3 / 2}}{\sqrt{G\left(M_1+M_2\right)}}\)
Put \(M_1=3 M_{S,} M_2=6 M_S\) and \(r=9 R\)
\(T^{\prime}=\frac{2 \pi \times 9^{3 / 2} \times R^{3 / 2}}{\sqrt{G\left(3 M_S+6 M_S\right)}}=\frac{2 \pi \times 9^{3 / 2} \times R^{3 / 2}}{9^{1 / 2} \sqrt{G M_S}}\) \(=9\left(\frac{2 \pi R^{3 / 2}}{\sqrt{G M_S}}\right)\)
\(\therefore \quad T^{\prime}=9 T\)
Value of \(n=9\).
For binary stars,
\(T^{\prime}=\frac{2 \pi r^{3 / 2}}{\sqrt{G\left(M_1+M_2\right)}}\)
Put \(M_1=3 M_{S,} M_2=6 M_S\) and \(r=9 R\)
\(T^{\prime}=\frac{2 \pi \times 9^{3 / 2} \times R^{3 / 2}}{\sqrt{G\left(3 M_S+6 M_S\right)}}=\frac{2 \pi \times 9^{3 / 2} \times R^{3 / 2}}{9^{1 / 2} \sqrt{G M_S}}\) \(=9\left(\frac{2 \pi R^{3 / 2}}{\sqrt{G M_S}}\right)\)
\(\therefore \quad T^{\prime}=9 T\)
Value of \(n=9\).
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