JEE Advanced · Physics · 24. Ray Optics
A large glass slab \(\left(\mu=\frac{5}{3}\right)\) of thickness 8 \(\mathrm{cm}\) is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius \(R \mathrm{~cm}\). What is the value of \(R\) ?
- A 2
- B 4
- C 6
- D 8
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation

\(
\frac{R}{t}=\tan \theta_C
\)
or \(\quad R=t\left(\tan \theta_C\right)\)
\(\text { But, } \quad \sin \theta_C=\frac{1}{\mu}=\frac{3}{5} \)
\( \therefore \tan \theta_C=\frac{3}{4} \)
\( \therefore R=\frac{3}{4} t=\frac{3}{4}(8 \mathrm{~cm})=6 \mathrm{~cm}\)
Hence the answer is 6 .
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